22. KCuF3 - IV

Cooperative Jahn-Teller effects, orbital ordering, superexchange, one-dimensional magnetism



Question: can we estimate experimentally-determined superexchange coupling constants from these calculations? Answer: More or less. (WEBNOTE: and this has also been done recently by people using fully-correlated quantum chemistry methods on small clusters..). Remember when we do HF calculations we have broken the spin symmetry. There is no sense in which the spin can be said to have a direction (the incorporation of 'non-collinear spins' with a vector magnetization density into electronic structure theory is an active area of research). We only have the concept of up and down spin - so this type of calculation corresponds most closely to an Ising model of the spin. You can actually derive an Ising model type expression which relates energy differences between magnetic states to the superexchange coupling constant, in terms of the energy difference, the spin moment per site, and a coordination number.. Now we don't expect this to work very well, but what we have found is that the accuracy of this treatment depends on the 'magnetic dimensionality' of the system. In 3D you might get around 60% of the true value, in 2D 50 %, in 1D about 40%. You expect that of course, because as you lower the dimensionality fluctuations become more important. For example, in KCuF3 we effectively have a one-dimensional magnet. In the real system, the zero-point fluctuations in the spin direction will be very important. What effect will they have? The main one will be to reduce the on-site magnetic moment. So if I just plug in the Hartree-Fock on-site moment into the Ising model expression, I get the numbers given in the above Table for the exchange coupling constants along the different axes, which don't agree very well with experiment, but at least we've reproduced the one dimensionality. If you arbitrarily plug in the experimental on-site moment to account for the zero point spin reduction, then we get essentially the right answer. So at least you can see where the error lies. I should stress again that this tends to work much better for higher dimensional magnetic systems, and these results are in fact the worst that I've seen, in terms of quantitative agreement..